

InterviewSolution
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A mother and her two daughters got a room constructed for ₹ 62,000. The elder daughter contributes 3/8 of her mother’s contribution while the younger daughter contributes ½ of her mother’s share. How much do the three contribute individually? |
Answer» From the question it is given that, A mother and her two daughters got a room constructed for = ₹ 62,000 Let us assume mother’s share be x, Then, The elder daughter’s contribute = 3/8 of her mother’s share = 3/8 x The younger daughter’s contribute = ½ of her mother’s share = ½ x So, mother’s share + elder daughter’s share + younger daughter’s share = ₹ 62,000 x + (3/8) x + ½ x = ₹ 62,000 The LCM of the denominators 1, 8 and 2 is 8 (1/1) = [(1×8)/ (1×8)] = (8/8) (3/8) = [(3×1)/ (8×1)] = (3/8) (1/2) = [(1×4)/ (2×4)] = (4/8) Then, (8/8) x + (3/8) x + (4/8) x = 62,000 (8x + 3x + 4x)/8 = 62,000 (15x/8) = 62,000 15x = 62,000 × 8 X = 496000/15 X = ₹ 33,066.6 ∴Mother’s share = ₹ 33,066.6 Elder daughter’s share = 3/8 of her mother’s share = 3/8 x = 3/8 × 33066.6 = ₹ 12,400 Younger daughter’s share = ½ of her mother’s share = ½ x = ½ × 33066.6 = ₹ 16,533.3 |
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