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A motorcycle moving with a speed of 5 ms^(-1)is subjected to an acceleration of 0.2 ms^(-2) for 10 second. Calculate (a) the speed (b) the distance travelled. |
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Answer» Solution :Here,` u = 5 ms ^(-1),a =0.2 ms ^(-2), t = 10` second `(a) v = u + at ` `= 5 ms ^(-1) + 0.2 ms ^(-2) xx 10 s ` ` = 5 ms ^(-1) + 5 ms ^(-1) = 10 ms ^(-1)` (b)` s = ut + 1/2 at ` `= 5 ms ^(-1) + 10S + 1/2 xx 0.2 ms ^(-2) xx (10 s ) ^(2)` `= 50 m + 10 m = 60 m` The speed of the MOTORCYCLE after 10 second is `10 ms ^(-1),` the distance TRAVELLED by the motorcycle is 60 m. |
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