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A nuclear of mass `M +deltam ` is at rest and decay into two daughter nuclei of equal mass `(M)/(2)` each speed is `c` The speed of daughter nuclei isA. `c(Delta m)/(M+Delta m)`B. `csqrt((2 Delta m)/(M))`C. `csqrt(( Delta m)/(M))`D. `csqrt((Delta m)/(M+Delta m))` |
Answer» According to conservation of momentum `0 = (M)/(2) V_(1) - (M)/(2)V_(2), V_(1) = V_(2)`, `Deltamc^(2) = (1)/(2) (M)/(2) V_(1)^(2) + (1)/(2).(M)/(2) V_(2)^(2)` |
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