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A nucleus with `Z = 92` emits the following in a sequence `a, beta^(bar) , beta^(bar)a,a,a,a,a, beta^(bar) , beta^(bar) , a, beta^(+) , beta^(+) , a ` Then `Z` of the resulting nucleus isA. 74B. 76C. 78D. 82 |
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Answer» Correct Answer - C ( c) `Z_("Resulting nucleus") = 92 - 8 xx 2 + 4 xx 1 - 2 xx 1 = 78`. |
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