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A nucleus `._Z^AX ` emits an `alpha`-particel. The resultant nucleus emits a `beta^(+)` particle. The respective atomic and mass numbers of the final nucleus will beA. `Z - 3, A - 4`B. `Z - 1, A - 4`C. `Z - 2, A - 4`D. `Z, A - 2` |
Answer» Correct Answer - A (a) `._Z^A X rarr ._(Z-2)^(A-4)Y + ._2^4 He rarr ._(Z-3)^(A-4) Z + ._1^0 B`. |
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