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A nut which can be broken by applying a force of 40 kgf, is broken by using a nut cracker having its handle 20 cm long, by placing it at a distance 2 cm from the hinge. Calculate the minimum force needed to break the nut. |
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Answer» Solution :Given, load=40 kgf, EFFORT=? load arm=2cm, effort arm=20 CM By the PRINCIPLE of MOMENTS, load`xx`load arm=effort`xx`effort arm `40kgfxx2cm=Exx10cm` `therefore E=(40xx2)/(20)kgf=4kgf`. |
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