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`A overset(lambda)rarr B overset(2 lambda)rarr C` `T=0 ,N_(0) , 0 `, ` T N_(1) N_(2) N_(3)` The ratio of `N_(1)" to "N_(2) ` is maximum I sA. at no time this is possibleB. ``2C. `1//2`D. `(ln2)/(2)` |
Answer» Correct Answer - b `(dN_(2))/(dt)=lambda N_(1) -2 lambda N_(2)` For `n_(2)` to be maximum, `(dN_(2))/(dt)=0` `rArr lambda N_(1)= 2 lambda N_(2)` or `(N_(1))/(N_(2)) =2`. |
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