1.

A particle executes simple harmonic motion according to the displacement equation `y = 10 cos(2 pi t + (pi)/(6))cm` where `t` is in second The velocity of the particle at `t = 1/6` second will beA. `-6.28ms^(-1)`B. `-0.628ms^(-1)`C. `0.628ms^(-1)`D. `6.28ms^(-1)`

Answer» Correct Answer - C
Velocity `v = (dv)/(dt) = (d)/(dt) [10 cos(2 pi t+ (pi)/(6))]`
`= - 20pi sin (2pi t + (pi)/(6)) cms^(-1)`
`v((1)/(6)) = - 20(3.14)sin((pi)/(3) + (pi)/(6)) cms^(-1)`
`= 62.8 cms^(-1)("numirically")[Using sin"(pi)/(2) = 1]`
`= 0.628ms^(-1)`


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