A particle is moving along a circle of radius `20cm`, with a linear ve – InterviewSolution

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1.	A particle is moving along a circle of radius `20cm`, with a linear velocity of `2m//s. Calculate the angular velocity of the particle.
Answer» `vecv=vecomegaxxvecr` as the angle between `vecr` and `vecomega` is `90^(@)`, so the magnitude of linear velocity is `\|vecv\|=r omega` `omega=(v)/(r )=(2xx100)/(20)` `=10"rad"s^(-1)`

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