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InterviewSolution
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A particle moves along a straight line `OX`. At a time `t` (in seconds) the distance `x` (in metre) of the particle is given by `x = 40 +12 t - t^3`. How long would the particle travel before coming to rest ?A. 24 mB. 40 mC. 56 mD. 16 m |
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Answer» Correct Answer - C Distance travelled by the particle is `x = 0 + 12 t - t^3` We know that velocity is rate of change of distance i.e., `v = (dx)/(dt)` `:. v = (d)/(dt) (40 + 12t - t^3) = 0 + 12 - 3t^2` but final velocity `v = 0` `12 = 3t^2 = 0` or `t^2 = (12)/(3) = 4` or `t = 2 s` Hence, distance travelled by the particle before coming to rest is given by `x = 40 + 12(2) - (2)^3 = 56 m`. |
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