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A particle of mass `1 mg` has the same wavelength as an electron moving with a velocity of `3 xx 10^(6) ms^(-1)`. The velocity of the particle isA. `3xx10^(-31)ms^(-1)`B. `2.7xx10^(-21)ms^(-1)`C. `2.7xx10^(-18)ms^(-1)`D. `9xx10^(-2)ms^(-1)` |
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Answer» Correct Answer - C We know that `p=(h)/(lamda)` or `mv=(h)/(lamda)` `therefore`As both particle and electrons having same wavelength therefore, their momentum will be equal to `impliesm_(p)v_(p)=m_(e)v_(e)` `implies v_(p)=(m_(e)v_(e))/(m_(p))` `=(9.1xx10^(-31)xx3xx10^(6))/(10^(-6))` `implies v_(p)=2.7xx10^(-18)ms^(-1)` |
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