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When a cathode ray tube is operated at 2912 V, the velocity of electrons is `3.2xx10^(7)ms^(-1)`. Find the velocity of cathode ray if the tube is operated at 5824V.A. `2.4xx10^(7)ms^(-1)`B. `5.2xx10^(7)ms^(-1)`C. `4.525xx10^(7)ms^(-1)`D. `2.4xx10^(6)ms^(-1)` |
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Answer» Correct Answer - C `v=sqrt((2eV)/(m))` Since, e and m are constant, `(v_(1))/(v_(2))=sqrt((V_(1))/(V_(2)))` or `v_(2)=v_(1)sqrt((V_(1))/(V_(2)))=3.2xx10^(7)sqrt((5824)/(2912))=4.525xx10^(7)ms^(-1)` |
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