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A beam of cathode rays is subjected to crossed electric (E ) and magnetic fields (B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given byA. `(B^(2))/(2VE^(2))`B. `(2VB^(2))/(E^(2))`C. `(2VE^(2))/(B^(2))`D. `(E^(2))/(2VB^(2))` |
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Answer» Correct Answer - D As the electron bea is not deflected, then `F_(m)=F_(e) implies Bev=Ee` or `v=(E)/(B)` . . . (i) As the electron moves from cathode to anode, its potential energy at the cathode appears as its kinetic energy at the anode. If V is the potential difference between the anode and cathode, then potential energy of the electron at cathode =eV. also kinetic energy of the electron at anode `=(1)/(2)mv^(2)`. according to law of conservation of energy , `(1)/(2)mv^(2)=eV` or `vsqrt((2eV)/(m))` . . (ii) From eqs. (i) and (ii), we have `sqrt((2eV)/(m))=(E)/(B)implies (e)/(m)=(E^(2))/(2VB^(2))`. |
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