InterviewSolution
Saved Bookmarks
| 1. |
The work function for aluminium is 4.125 eV. The cut-off wavelength for photoelectric effect for aluminium will beA. 420 nmB. 350 nmC. 300 nmD. 200 nm |
|
Answer» Correct Answer - C The work function for aluminium, `W_(0)=4.125eV` `=4.125xx1.6xx10^(-19)=6.6xx10^(-19)J` the relation for work function is given by `W_(0)=(hc)/(lamda)` (where, `lamda` is the cut-off wavelength) `6.6xx10^(-19)=(6.6xx10^(-34)xx3xx10^(8))/(lamda)` `lamda=(6.6xx10^(-34)xx3xx10^(8))/(6.6xx10^(-19))` `=(19.8xx10^(-26))/(6.6xx10^(-19))` `=3xx10^(-7)m` `=300xx10^(-9)m=300nm` |
|