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A particle `X` moving with a certain velocity has a debragile wave length of `1.72Å`, If particle `Y` has a mass of `50%` that of `X` and velocity `50%` that of `X`, debroglies wave length of `Y` will be `-`A. `3Å`B. `5.33Å`C. `6.88Å`D. `48Å` |
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Answer» Correct Answer - 3 `lambda=(h)/(mv)" "lambda_(x)=(h)/(m_(x)v_(x))" "lambda_(y)=(h)/(m_(y)v_(y))` `m_(y)=(m_(x))/(2)" "lambda_(y)=(V_(y))/(2)" "(lambda_(x))/(lambda_(y))=(1)/(4)` `lambda_(y)=1.72xx4=6.88A` |
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