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A pebble thrown vertically upwards with an initial velocity 50 m s^(-1)comes to a stop in 5 s. Find the retardation. |
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Answer» Solution :GIVEN u = 50 `m s ^(-1) v=0 , t=5 s ` Acceleration a = `(v-u ) /(t) = (0-50 m s^(-1))/(5s)` `= - 10 m s^(-2)` Hence RETARDATION = 10 m `s^(-2)` . |
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