1.

A pebble thrown vertically upwards with an initial velocity 50 m s^(-1)comes to a stop in 5 s. Find the retardation.

Answer»

Solution :GIVEN u = 50 `m s ^(-1) v=0 , t=5 s `
Acceleration a = `(v-u ) /(t) = (0-50 m s^(-1))/(5s)`
`= - 10 m s^(-2)`
Hence RETARDATION = 10 m `s^(-2)` .


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