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A perfect carnot engine utilizes an ideal gas the source temperature is 500 K and sink temperature is 375 K. If the engine takes 600 k cal per cycle from the source, calculate The efficiency of engine |
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Answer» Solution :`T_1=500K,T_2=375K` `Q_1` = HEAT ABSORBED = 600 k CAL `eta=1-T_2//T_1=125/500=0.25` `=25%` |
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