1.

A person is unable to see objects nearer than 50 cm. He wants to read a book placed at a distance of 25 cm. Find the nature, focal length and power of the lens he requires for his spectacles.

Answer»

Solution :This person has defect of Hypermetropia which is far SIGHTEDNESS that means the image is formed beyond the retina so it requires a convergent lens to get focused at retina.
Now corrective measure is `u=-25cm`
`V=-50cm`
`(1)/(f)=(1)/(v)-(1)/(u)`
`(1)/(f)=(1)/(-50)-(1)/(-25)`
`=-(1+2)/(50)=(1)/(50)`
`f=50cm`
`P=(1)/(f)`
`P=(100)/(50)=2D`
Focal length = 50 CM.
Power = 2 D


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