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A person wears glasses of power `-2.5D`. The defect of the eye and the far point of the person without the glasses are, respectivelyA. farsightedness,`40cm`B. nearsightedness, `40 cm`C. astigmatism, `40 cm`D. nearsightedness, `250 cm` |
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Answer» Correct Answer - B `f = (100)/(P)cm = (100)/(-2.5)=- 40cm` `(1)/(-(F.P.)) - (1)/(-("distance of object")) = (1)/(f)` `(1)/(-(F.P.)) - (1)/(oo)=(1)/(-40) rArr F.P. = 40cm` `F.P. = 40 cm`, nersightedness |
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