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A person with a myopia eye cannot see objects beyond a distance of 1.5 m. What would be the power of the corrective lens used to restore proper vision ? |
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Answer» <P> Solution :The corrective lens should make the OBJECTS at infinity appear at the far point.`:.`For object at infinity, object distance `= u = -oo`. For the myopic EYE, far-point distance, v = -1.5 m. By lens formula `(1)/(f) = (1)/(u) - (1)/(v) = (1)/(-1.5) - (1)/(-oo) = (1)/(-1.5) + 0 = (1)/(-1.5)` f = -1.5 m. POWER , `P = (1)/("f(in m)") = (1)/(1.50) = -0.67 D` Negative sign shows that the corrective lens is a concave. |
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