1.

A person with a myopia eye cannot see objects beyond a distance of 1.5 m. What would be the power of the corrective lens used to restore proper vision ?

Answer»

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Solution :The corrective lens should make the OBJECTS at infinity appear at the far point.
`:.`For object at infinity, object distance `= u = -oo`.
For the myopic EYE, far-point distance, v = -1.5 m.
By lens formula
`(1)/(f) = (1)/(u) - (1)/(v) = (1)/(-1.5) - (1)/(-oo) = (1)/(-1.5) + 0 = (1)/(-1.5)`
f = -1.5 m.
POWER , `P = (1)/("f(in m)") = (1)/(1.50) = -0.67 D`
Negative sign shows that the corrective lens is a concave.


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