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A photon of frequency n causes photoelectric emmission from a surfece with thereshold .The de Broglie wavelength `lambda ` of the photoelectrn emitted is given asA. `Delat n = (h)/(2m lambda)`B. `Delat n = (h)/(lambda)`C. `[(1)/(v_(0)) - (1)/(v)] = (mc^(2))/(h)`D. `lambda = sqrt((h)/(2m Delta n))` |
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Answer» Correct Answer - D `E_(1)= IE + KE` or `E_(1) = `Threshold E (or) work function `+ KE` `(hv = hv_(0) + (1)/(2) m u^(2))` or `hn = hn_(0) + (1)/(2) m u^(2)` `(1)/(2) m u^(2) = h(n - n_(0)) = h Delta n`…….(i) `(lambda = (h)/(mu) ,:. U = (h)/(m lambda))` Subsitute the value n in equation (i) `(1)/(2) m(h^(2))/(m^(2)lambda^(2)) = h DRelta n` `(h)/(2lambda^(2)m) = Delta n ` `:. lambda = sqrt((h)/(2m Delta n))` |
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