InterviewSolution
Saved Bookmarks
| 1. |
A photosensitve metallic surface has work fuction ` hv_0` If photons of ` 2hv_0` fall on the suface , the electrons come out with a maximum velocity of ` 4xx 10^6 m//s` . If photon energy is increases to ` 5hv_0` the maximum velocity of photoelectrons will be:A. ` 2xx 10^7 m//s`B. `82xx 10^6 m//s`C. ` 2xx 10^76m//s`D. ` 8xx 10^5 m//s` |
|
Answer» Correct Answer - B ` 2h-0 = hv_0 + K.E._1` , or `hv_0 = K.E. _1 = 1/2 mu_1^2` Now `5 hv_0= hv_0 + K.E._2` `K. E._2 = 4 hv_0 = 1/2 mu_1=2^2` ` :. U_2^2 /u_1^2 =4` or ` u_2 = 2 u_1` . |
|