1.

A piece of wire of resistances R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R' then the ratio R/R' is

Answer»

`1/25`
`1/5`
5
25

Solution :When a wire of resistance R is cut in five EQUAL parts, resistance of each PAT `R_1=R/5 OMEGA` Now, all these pieces are joined in parallel, HENCE,
`1/R.=1/R_1+1/R_1+....5 time s=5/R_1or R.=R_1/5 =1/5 times R/5 =R/25 therefore R/R.=R/((R//25))=25.]`


Discussion

No Comment Found

Related InterviewSolutions