1.

A point traversed half the distance with a velocity `v_0`. The remaining part of the distance was covered with velocity `v_1` for half the time, and with velocity `v_2` for the other half of the time. Find the mean velocity of the point averaged over the whole time of motion.

Answer» Correct Answer - `< < v > > =2v_0(v_1+v_2)//(2v_0+v_1+v_2)`
Let s be the total distance traversed by the point and `t_1` the time taken to cover half the distance. Further let `2t` be the time to cover the rest half of the distance.
Therefore `s/2=v_0t_1` or `t_1=(s)/(2v_0)` (1)
and `s/2=(v_1+v_2)t` or `2t=(s)/(v_1+v_2)` (2)
Hence the sought average velocity
`lt v gt =(s)/(t_1+2t)=(s)/([s//2v_0]+[s//(v_1+v_2)])=(2v_0(v_1+v_2))/(v_1+v_2+2v_0)`


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