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Two relativistic particles move at right angles to each other in a laboratory frame of reference, one with the velocity `v_1` and the other with the velocity `v_2`. Find their relative velocity. |
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Answer» The approach velocity is defined by `vecV_(approach)=(dvecr_1)/(dt)-(dvecr_2)/(dt)=V_1-vecV_2` in the laboratory frame. So `V_(approach)=sqrt(v_1^2+v_2^2)` On the other hand, the relative velocity can be obtained by using the velocity addition formula and has the componets `[-v_1, v_2sqrt(1-(v_1^2/c^2))]` so `V_r=sqrt(v_1^2+v_2^2-(v_1v_2^2)/(c^2))` |
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