The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as `T=as^2`, where a is ticle as a function of s.

The kinetic energy of a particle moving along a circle of radius R dep

1.	The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as `T=as^2`, where a is ticle as a function of s.
Answer» We have `T=1/2mv^2=as^2` or, `v^2=(2as^2)/(m)` (1) Differentiating Eq. (1) with respect to time `2vw_t=(4as)/(m)v` or, `w_t=(2as)/(m)` (2) Hence net acceleration of the particle `w=sqrt(w_t^2+w_n^2)=sqrt(((2as)/(m))^2+((2as)/(mR))^2)=(2as)/(m)sqrt(1+(s//R)^2)` Hence the sought force, `F=mw=2assqrt(1+(s//R)^2)`

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The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as `T=as^2`, where a is ticle as a function of s.

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