InterviewSolution
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InterviewSolution
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A pot conical shaped , the radius and heightof which is 6 cm and 8 cmrespectively , is fulfilled with water of this pot in sucha waythat it just touches the two sides of the pot . So , how many part of the waterof the pot will over flow ? |
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Answer» Solution :In the figure beside , AD = 6 cm and DC = 8 cm ` :. AC = SQRT(CD^(2)+AD^(2))` ` = sqrt(8^(2) + 6^(2)) ` cm ` = sqrt(64 + 36)` cm 10 cm Now , in the right - angled trinagles `Delta ACD and Delta EOC` , we get ` ANGLE ACD = angle ECO` Let the radius of the sphere be x cm ` :.` as per figure , AD = AE = 6 cm ` :.EC = (AC- AE) = (10-6)` cm = 4 cm Again , ` Delta ADS ~ Delta EOC , :. (DC)/(AD) = (EC)/(EO)` ` rArr 8/6 = 4/3 rArr x = (4xx 6)/8 = 3` ` :.` the radius of the sphereis 3 cm So , the volume of the sphere` = 4/3pi xx 3^(3) ` cc = 36 ` pi` cc Again, the volume of the CONICAL pot ` = 1/3 xx pi xx 6^(2) xx 8 ` cc = ` 96 pi ` cc So , the required part ` = (36pi)/(96pi) = 3/8` Hence `3/8` part of the WATER of the pot will overflow 
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