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InterviewSolution
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A projectile is fired with kinetic energy 1 kj. If itsrange is maximum, what will be its kinetic energyat the highest point of its trajectory ? |
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Answer» Solution :here `(1)/(2) mv^(2)=1|KJ=1000J, THETA=45^(@)` At the highest POINT, K.E. `=(1)/(2) m(V cos theta)^(2)=(1)/(2)(mv^(2))/(2)=(1000)/(2)=500J`. |
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