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A pump can fill a tank with water in 3 hours. Because of a leak it took \(3\frac{1}{5}hours\) to fill the tank. The leak can drain all the water in the tank in1). 54 hours2). 36 hours3). 42 hours4). 48 hours |
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Answer» The pump can FILL the tank in 3 HOURS ∴ Part of tank filled by the pump in 1 hour = 1/3 Let, the leak can DRAIN all the WATER in ‘x’ hours ∴ Part of tank leaked by the drain in 1 hour = 1/x Given, Because of a leak pump took $(3\frac{1}{5}hours = \frac{{16}}{5}hours)$ to fill the tank $(\THEREFORE \frac{1}{3} \times \frac{{16}}{5} - \frac{1}{x} \times \frac{{16}}{5} = 1)$ ⇒ 16/15 - 16/5x = 1 ⇒ 16/5x = 16/15 – 1 = 1/15 ⇒ 5x = 16 × 15 ⇒ x = 48 hours |
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