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A racing car has a uniform acceleration of 4 ms^(-2). What distance it covers in 10 s after the start ? |
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Answer» Solution :Given : acceleration = `4ms^(-2)` TIME = 10s and initial velocity =0 Formula : `s=ut+1//2 at^2` distance covered `s=0 XX t + 1//2 xx 4ms^(-2) xx (10s)^2` `s=1//2xx4 ms^(-2) xx 100 s^2` =1/2 x 400 m =200 m |
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