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A radioactiev nuleus `X` deays to a stable nuleus `Y`. Then, time graph of rate of formation of `Y` against time `t` will be:A. B. C. D. |
Answer» Correct Answer - c `N=N_(0) e^(- lmabda t),N_(Y) =N_(0)(1-e^(-lambda t))` Rate of formation of `Y` is `(dN)/(dt) =+ lambda N_(0)e^(-lambda t)` Which decreases exponentially with time. |
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