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A radioactive element emits `200` particle per second. After three hours `25` particle per second are emitted. The half-life period of element will beA. 50 minutesB. 60 minutesC. 70 minutesD. 80 minutes |
Answer» Correct Answer - B (b) `R = (dN)/(dt) prop N rArr (R_2)/(R_1) = (N_2)/(N_1)` But `(N_2)/(N_1) = ((1)/(2))^(t_1//2) rArr (25)/(200) = (1)/(8) = ((1)/(2))^3 rArr (t)/(t_(1//2)) = 3` `:. t_(1//2) = (t)/(3) = (3)/(3) = 1 hour = 60` minutes. |
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