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A radioactive element with half-life 6.5 hr has `48 xx 10^(19)` atoms. Number of atoms left after 26 hrA. `24 xx 10^(19)`B. `12 xx 10^(19)`C. `3 xx 10^(19)`D. `6 xx 10^(19)` |
Answer» Correct Answer - C `N_(t) = N_(0) ((1)/(2))^(n) = 48xx10^(19) ((1)/(2))^(26//65)` `= 48 xx 10^(19) ((1)/(2))^(4) = 3xx 10^(19)` |
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