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A radioactive isotope decays at such a rate that after 96 minutes only `(1)/(8)th` of the original amount remains. The half-life of this nuclide in minutes isA. 12B. 24C. 32D. 48 |
Answer» Correct Answer - C `lamda = (2.303)/(t) "log" ([N_(0)])/([N]) = (2.303)/(96) "log" (1)/(1//8)` `:. T_(1//2) = (0.693)/(lamda) = (0.693)/(0.0216) = 32.0` min |
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