A radioactive material decays by simulataneous emission of two particle from the with respective half - lives `1620` and `810` year . The time , in year , after which one - fourth of the material remains isA. 4860B. 2430C. 3240D. 1080

A radioactive material decays by simulataneous emission of two particl

1.	A radioactive material decays by simulataneous emission of two particle from the with respective half - lives `1620` and `810` year . The time , in year , after which one - fourth of the material remains isA. 4860B. 2430C. 3240D. 1080
Answer» Correct Answer - D (d) `lamda = lamda_1 + lamda_2` `rArr (1)/(T) = (1)/(T_1) +(1)/(T_2)` `:. T = (T_1 xx T_2)/(T_1 + T_2) = (810 xx 1620)/(810 + 1620) = 540 years` Hence, `(1)/(4) th` of material remain after `1080 years`.

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A radioactive material decays by simulataneous emission of two particle from the with respective half - lives `1620` and `810` year . The time , in year , after which one - fourth of the material remains isA. 4860B. 2430C. 3240D. 1080

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