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A radioactive sample is `alpha-`emitter with half life `138.6` days is observed by a student to have `2000` disintegration/sec. The number of radioactive nuclei for given activity are.A. `3.45 xx 10^10`B. `1 xx 10^10`C. `3.45 xx 10^15`D. `2.75 xx 10^11` |
Answer» Correct Answer - A (a) Activity of substance that has `2000` disintegration/sec `=(2000)/(3.7 xx 10^10) = 0.054 xx 10^-6 ci = 0.054 mu ci` The number of radioactive nuclei having activity `A` `N = (A)/(lamda) = (2000 xx T_(1//2))/(log_e 2)` =`(2000 xx 138.6 xx 24 xx 3600)/(0.693) = 3.45 xx 10^10`. |
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