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A radioactive substance has a half-life of `1` year. The fraction of this material, that would remain after `5` years will be.A. `(1)/(32)`B. `(1)/(5)`C. `(1)/(2)`D. `(4)/(5)` |
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Answer» Correct Answer - A (a) Number of half lives `n = (5)/(1) = 5` Now `(N)/(N_0) = ((1)/(2))^n rArr (N)/(N_0) = ((1)/(2))^5 = (1)/(32)`. |
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