A radioactive substance has `t_(1//2)` 60 minutes. After 3 hrs, what precentage of radioactive substance will remainA. 0.5B. 0.75C. 0.25D. 0.125

A radioactive substance has `t_(1//2)` 60 minutes. After 3 hrs, what p

1.	A radioactive substance has `t_(1//2)` 60 minutes. After 3 hrs, what precentage of radioactive substance will remainA. 0.5B. 0.75C. 0.25D. 0.125
Answer» Correct Answer - D Amount left `= (N_(0))/(2^(3)) = (100)/(8) = 12.5%`

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A radioactive substance has `t_(1//2)` 60 minutes. After 3 hrs, what precentage of radioactive substance will remainA. 0.5B. 0.75C. 0.25D. 0.125

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