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A radioactive with decay constant `lambda` is being produced in a nuclear ractor at a rate `q_(0)` per second, where `q_(0)` is a positive constant and t is the time. During each decay, `E_(0)` energy is released. The production of radionuclide starts at time `t=0`. Which differential equation correctly represents the above process?.A. `(dN)/(dt)+a_(0)t=lambda N`B. `(dN)/(dt)-lambda N=a_(0)t`C. `(dN)/(dt)+lambda N=a_(0)t`D. `(dN)/(dt)+a_(0)t= - lambda N` |
Answer» Correct Answer - C `(dN)/(dt)=a_(0)t-lambdaN, (dN)/(dt)+lambda N=a_(0)t` |
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