1.

A radon specimen emits radiation of 3.7xx10^(3)GB q pe second. Convert this disintegration in terms of curie. (one curie=3.7xx10^(10) disintegration per second)

Answer»

Solution :1 BQ = one disintegration PER second , one curie = `3.7 xx 10^(10)`Bq
`1Bq= (1)/(3.7 xx 10^(10))` curie
` therefore 3.7 xx 10^(3) GBQ= 3.7 xx 10^(3) xx 10^(9) xx (1)/(3.7 xx 10^(10))`
= 100 curie


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