A ray of light strikes a glass slab 5 cm thick, making an angle of incidence equal to 30^(@). (a) Draw a ray diagram showing the emergent ray and the refracted ray through the glass block. The refractive index of glass is 1*5. (b) Measure the lateral displacement of the ray. The sin 19*5^(@)=1//3.

A ray of light strikes a glass slab 5 cm thick, making an angle of inc

1.	A ray of light strikes a glass slab 5 cm thick, making an angle of incidence equal to 30^(@). (a) Draw a ray diagram showing the emergent ray and the refracted ray through the glass block. The refractive index of glass is 15. (b) Measure the lateral displacement of the ray. The sin 195^(@)=1//3.
Answer» SOLUTION :(a) : `mu=15,i=30^(@)` Let us FIRST calculate the angle of refraction R. From Snell.s law, `(SINI)/(sinr)=mu` `therefore sinr=(sini)/(mu)=(sin30^(@))/(15)=(1//2)/(15)=(1)/(3)` or `r=195^(@)` (since `sin195^(@)=1//3`) The ray diagram is given in FIGURE. the refracted ray is drawn with angle of refraction `195^(@)` and emergent ray is drawn parallel to the incident ray. (b) Lateral displacement=1 cm nearly (on proper scale).