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A receptacle is filled with a mixture of two liquids L1 and L2 in the ratio of 7 : 5. Due to poor handling, 9 litres of mixture fell from the receptacle and the volume was made up with L2, thus the ratio of the both liquids in the mixture becomes 7 : 9. Find the initial quantity of L1 in the mixture.1). 24 litres2). 21 litres3). 26 litres4). 28 litres |
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Answer» Let the receptacle initially contains 7x and 5x of mixtures L1 and L2 respectively. Remaining quantity of L1, = (7x – 7 × 9/12) = (7x - 21/4) litres Remaining quantity of L2, = (5x – 5 × 9/12) = (5x - 15/4) litres According to the QUESTION, [(7x - 21/4)/ (5x - 15/4) + 9] = 7/9 ⇒ (28x - 21)/ (20X + 21) = 7/9 ⇒ 252x - 189 = 140x + 147 ⇒ 112x = 336 ⇒ x = 3 ∴ Initial quantity of L1 in the mixture = 7 × 3 = 21 litres |
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