A right angled prism is to be made by selecting a proper material and

1.	A right angled prism is to be made by selecting a proper material and the angles A and B `(B
Answer» (`a`) As already discussed `Agetheta_(c )`, `Bgetheta_(c )` Also `BleA` Case : `1 : B=A=pi//4rArrtheta_(c )lepi//4`…..(`1`) Case `2 : B lt A`. Hence, for reflection at both faces `B gt theta_(c )` But, `B lt pi//4rArrtheta_(c ) lt pi//4` (as `2B lt pi//2`).......(`2`) Combining Eqs. (`1`) and (`2`), we get `theta_(c ) le pi//4` `(1)/(n) le(1)/(sqrt(2))rArrn ge sqrt(2)` `n_(min)=sqrt(2)` (`b`) This pertains to case (`2`) Hence, `theta_(c ) lt 30^(@)` But `theta_(c )=sin^(-1)(3//5)` which is more than `30^(@)` and hence, it is not possible.

Discussion

No Comment Found

Related InterviewSolutions

Red light of wavelength `6500 Å` from a distant source falls on a slit `0.50 mm` wide. Calculate the distance between first two dark bands on each side of central bright band in the diffraction pattern observed on a screen placed `1.8 m` from the slit.
The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringe from the centre is
The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringe from the centre isA. `2`B. `1//2`C. `4`D. `16`
Among the two interfering monochromatic sources A and B, A is ahead of B in phase by `66^@`. If the observation be taken from point P, such that `PB-PA=lambda//4`. Then the phase difference between the waves from A and B reaching P isA. `156^(@)`B. `140^(@)`C. `136^(@)`D. `126^(@)`
The radius of curvature of curved surface of a thin plano-convex lens is `10 cm` and the refractive index is `1.5`. If the plano surface is silvered, then the focal length will be.A. 15 cmB. 20 cmC. 5 cmD. 10 cm
Calculate the resolving power of a microscope with cone angle of light falling on the objective equal to `60^(@)`. Take `lambda = 600 nm mu` for air `= 1`.
The diameter of the pupil of human eye is about `2 mm`. Human eye is most sensitive to the wavelength `555 nm`. Find the limit of resolution of human eye.
Assume that light of wavelength `6000 Å` is coming from a star. What is the limit of resolution of a telescope whose objective has a diameter of 100 inch ? (NCERT Solved example)
A central fringe of interference pattern produced by light of wavelength `6000 Å` is shifted to the position of 5th bright fringe by introducing thin film of `mu = 1.5`. Calculate thickness of the film.
Laser light of wavelength `630 nm` incident on a pair of slits produces an interference pattern where bright fringes are separated by `8.1 mm`. Another light produces the interference pattern, where the bright fringes are separated by `7.2 mm`. Calculate the wavelength of second light.

A right angled prism is to be made by selecting a proper material and the angles A and B `(B

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment