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A rocket of mass 3 xx 10^(6) Kg takes off from a launching pad and acquires vertical velocity of 1 km/s and an altitude of 25m calculate its potential energy and kinetic energy

Answer»

SOLUTION :Given m = `3 xx 10^(6)` kg, v = 1 km/s or
1000 m/s and h = 20 m
Potential energy = mgh = `3 xx 10^(6) kg xx 10m//s^(2) xx 25m = 7.5 xx 10^(8) J`
Kinetic energy = `1/2 mv^(2) = 1/2 xx 3 xx106 xx 1000 m//s xx 1000 m//s = 1.5 xx 10^(12) J`


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