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A sample contains `16 gm` of radioactive material, the half-life of which is two days. After `32` days, the amount of radioactive material left in the sample isA. Less than `1 mg`B. `(1)/(4) gm`C. `(1)/(2) gm`D. 1 gm |
Answer» Correct Answer - A (a) Remaining amount =`16 xx ((1)/(2))^(32//2) = 16 xx ((1)/(2))^16 = ((1)/(2))^12 lt 1 mg`. |
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