A sample of 12 M Concentrated hydrochloric acid has a density 1.2g L-1

1.	A sample of 12 M Concentrated hydrochloric acid has a density 1.2g L-1 . Calculate the molality.
Answer» Given: Molarity = 12 M HCI Density of the solution = 1.2 g L^-1 In 12 M HCl solution, there are 12 moles of HCl in 1 litre of the solution. Molality = (No. of moles of solute) / (Mass of solvent(in Kg.)) Calculate mass of water (solvent) Mass of 1 liter HCI solution = density x volume = 1.2g mL^-1 x 1000 mL = 1200g Mass of HCI = (No. of moles of HCI) x (molar mass of HCI) = 12 mol x 36.5 g mol^-1 = 438g Mass of waler = (mass of HCI solution) – (mass of HCI) = 1200 – 438 = 762 g Molalily = 12/0.762 = 15.75 m

A sample of 12 M Concentrated hydrochloric acid has a density 1.2g L-1 . Calculate the molality.

Answer»

Given:

Molarity = 12 M HCI

Density of the solution = 1.2 g L^-1

In 12 M HCl solution, there are 12 moles of HCl in 1 litre of the solution.

Molality = (No. of moles of solute) / (Mass of solvent(in Kg.))

Calculate mass of water (solvent)

Mass of 1 liter HCI solution = density x volume

= 1.2g mL^-1 x 1000 mL

= 1200g

Mass of HCI = (No. of moles of HCI) x (molar mass of HCI)

= 12 mol x 36.5 g mol^-1

= 438g

Mass of waler = (mass of HCI solution) – (mass of HCI)

= 1200 – 438

= 762 g

Molalily = 12/0.762 = 15.75 m

Discussion

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