1.

A sample of `H_(2)SO_(4)` (density `1.8 g mL^(-1)`) is labelled as `74.66%` by weight. What is molarity of acid? (Give answer in rounded digits)

Answer» Let `V=1l t=1000ml`
mass of solution `=1800gm`
So mass of solute `=1800xx(74.66)/(100)gm`
So molarity `=` moles of solute in `1l t=(18xx74.66)/(98)=13.71M`


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