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A satellite orbits the earth at a height 'R' from the surface. How much energy must be expended to rocket the satellite out of earth's gravitational influence? |
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Answer» SOLUTION :The energy required to pull the satellite from earth influence should be EQUAL to the total energy with which it is revolving around the earth The K.E. of satellite `=(1)/(2)mv^(2)= (1)/(2)m (GM)/(R+h), "" v= sqrt((GM)/(R+h))` The P.E. of satellite `= -(GMm)/(R+h)` `T.E.= (1)/(2)(MGM)/(2(R+h))-(GMm)/((R+h))=(1)/(2)(GMm)/((R+h))` Energy required will be `(+(1)/(4)(GMm)/((R)))`. |
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