1.

A satellite orbits the earth at a height 'R' from the surface. How much energy must be expended to rocket the satellite out of earth's gravitational influence?

Answer»

SOLUTION :The energy required to pull the satellite from earth influence should be EQUAL to the total energy with which it is revolving around the earth
The K.E. of satellite `=(1)/(2)mv^(2)= (1)/(2)m (GM)/(R+h), "" v= sqrt((GM)/(R+h))`
The P.E. of satellite `= -(GMm)/(R+h)`
`T.E.= (1)/(2)(MGM)/(2(R+h))-(GMm)/((R+h))=(1)/(2)(GMm)/((R+h))`
Energy required will be `(+(1)/(4)(GMm)/((R)))`.


Discussion

No Comment Found