A silvery white metal on treatment with NaOH and HCl liberated H_(2) gas to form B and C respectively , the metal A will not react with acid D due to the formation of a passive film on the surface . Hence it is used for transporating acid D. Identify A, B, C, D and support your answer with balanced equations.

A silvery white metal on treatment with NaOH and HCl liberated H_(2) g

1.	A silvery white metal on treatment with NaOH and HCl liberated H_(2) gas to form B and C respectively , the metal A will not react with acid D due to the formation of a passive film on the surface . Hence it is used for transporating acid D. Identify A, B, C, D and support your answer with balanced equations.
Answer» Solution : A silvery white metal metal (A) is aluminium (Al) (ii) Aluminium REACTS with NaOH to form B which is known as sodium meta aluminate with the liberation of `H_(2)` gas (iii) Aluminium reacts with HCl to form aluminium chloride which is known as C with the liberation of `H_2)` gas . `2Al+6HClrightarrow2AlCl_(3)+3H_(2)uparrow` (iv) Aluminium deos not react with conc.nitric acid `(HNO_(3)` Which is known as D, due to the formation of a passive FLN on the surface