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A simple pendulum hangs the celling of a car if the car acceleration with a uniform acceleration , the frequency of the simple pendulum willA. increaseB. decreaseC. become infiniteD. remain constrant |
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Answer» Correct Answer - A In this case frequency of oscillation is given by `n = (1)/(2pi) sqrt(sqrt(g^(2) +a^(2))/(l))` where a is the acceleration of car if a increase then `n` also increase |
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